a-1.
The number of units that passed inspection is 176 + 335 + 108 = 619.
a-2.
The number of units that failed inspection is 16 + 51 + 34 = 101.
b.
The number of units inspected by inspectors with high experience is 108 + 34 = 142.
c.
The proportion of units inspected by inspectors with low experience is (176 + 16) / (176 + 335 + 16 + 51 + 108 + 34) = 192 / 720 = 0.27 (rounded to 2 decimal places).
d.
The proportion of units inspected by inspectors with medium experience and failed inspection is 51 / (335 + 51) = 0.13 (rounded to 2 decimal places).
he following contingency table shows inspection records for 720 units of a particular product. The records have been cross-classified by the inspector’s decision (Pass and Fail) and the inspector’s experience (Low, Medium, and High).
Decision Experience
Low Medium High
Pass 176 335 108
Fail 16 51 34
a-1. How many of the units passed inspection?
a-2. How many of the units failed inspection?
b. How many of the units were inspected by inspectors with high experience?
c. What proportion of the units were inspected by inspectors with low experience? (Round your answer to 2 decimal places.)
d. What proportion of the units were inspected by inspectors with medium experience and failed inspection? (Round your answer to 2 decimal places.)
1 answer