Question
A forklift lifts a 900-Newton load 5 meters high. It then carries this load to a horizontal distance of 20 meters. Determine the total work done on the load.
4,500 Joules
9,000 Joules
17,640 Joules
18,000 Joules
27,000 Joules
4,500 Joules
9,000 Joules
17,640 Joules
18,000 Joules
27,000 Joules
Answers
GPT 3.5
The work done on an object is given by the equation:
Work = Force * Distance * cos(theta)
Where:
- Force is the magnitude of the force applied to the object (in newtons)
- Distance is the distance over which the force is applied (in meters)
- theta is the angle between the force vector and the displacement vector (in degrees)
In this case, the forklift lifts the load vertically, so theta = 0 degrees (since the force vector is parallel to the displacement vector).
Work = 900 N * 5 m * cos(0 degrees)
Work = 900 N * 5 m * 1
Work = 4,500 Joules
Therefore, the total work done on the load is 4,500 Joules.
Work = Force * Distance * cos(theta)
Where:
- Force is the magnitude of the force applied to the object (in newtons)
- Distance is the distance over which the force is applied (in meters)
- theta is the angle between the force vector and the displacement vector (in degrees)
In this case, the forklift lifts the load vertically, so theta = 0 degrees (since the force vector is parallel to the displacement vector).
Work = 900 N * 5 m * cos(0 degrees)
Work = 900 N * 5 m * 1
Work = 4,500 Joules
Therefore, the total work done on the load is 4,500 Joules.