Question
A chemist reacted 57.50 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.
2Na + Cl2 → 2NaCl
If the percentage yield of the reaction is 86%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors.
2Na + Cl2 → 2NaCl
If the percentage yield of the reaction is 86%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors.
Answers
Answered by
GPT 3.5
To find the actual yield, we need to first calculate the theoretical yield using stoichiometric calculations.
From the balanced chemical equation, we can see that 2 moles of sodium react with 1 mole of chlorine gas to produce 2 moles of sodium chloride.
1 mole of sodium has a molar mass of 22.99 g.
Therefore, 57.50 g of sodium is equal to 57.50 g / 22.99 g/mole = 2.50 moles of sodium.
Since the reaction is 2 moles of sodium to 2 moles of sodium chloride, we can deduce that 2.50 moles of sodium will produce 2.50 moles of sodium chloride.
The molar mass of sodium chloride is 58.44 g/mole.
Therefore, the theoretical yield of sodium chloride is 2.50 moles x 58.44 g/mole = 146.10 g.
Now, to find the actual yield, we can use the formula for percentage yield:
percentage yield = (actual yield / theoretical yield) x 100
Rearranging the formula to solve for the actual yield:
actual yield = (percentage yield / 100) x theoretical yield
actual yield = (86 / 100) x 146.10 g
actual yield = 0.86 x 146.10 g
actual yield = 125.67 g
Therefore, the actual yield of sodium chloride is 125.67 grams.
From the balanced chemical equation, we can see that 2 moles of sodium react with 1 mole of chlorine gas to produce 2 moles of sodium chloride.
1 mole of sodium has a molar mass of 22.99 g.
Therefore, 57.50 g of sodium is equal to 57.50 g / 22.99 g/mole = 2.50 moles of sodium.
Since the reaction is 2 moles of sodium to 2 moles of sodium chloride, we can deduce that 2.50 moles of sodium will produce 2.50 moles of sodium chloride.
The molar mass of sodium chloride is 58.44 g/mole.
Therefore, the theoretical yield of sodium chloride is 2.50 moles x 58.44 g/mole = 146.10 g.
Now, to find the actual yield, we can use the formula for percentage yield:
percentage yield = (actual yield / theoretical yield) x 100
Rearranging the formula to solve for the actual yield:
actual yield = (percentage yield / 100) x theoretical yield
actual yield = (86 / 100) x 146.10 g
actual yield = 0.86 x 146.10 g
actual yield = 125.67 g
Therefore, the actual yield of sodium chloride is 125.67 grams.