3x + 2x = 0
5x = 0
x = 0
10. Jill solves the equation 3(x−5)+2x=0
. Fill in the blanks for each step with the correct values:(3 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
3x+
+2x=0
5x=
Response area
x=
Response area
17 answers
FILL IN THE DANG BLANKS DUMMY
3x + __ + 2x = 0
5x = 0
x = 0
5x = 0
x = 0
WRONG ANSWER STUPID
Apologies for the mistake. Let's try again.
3(x - 5) + 2x = 0
3x - 15 + 2x = 0
5x - 15 = 0
5x = 15
x = 3
3(x - 5) + 2x = 0
3x - 15 + 2x = 0
5x - 15 = 0
5x = 15
x = 3
Solve the equation filling in the steps: 2(x−3)+21=−3
(6 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Distribute to get
Combine like terms to get Response area
Use the (choose a property) Response area to get (resulting equation) Response area
Use the (choose a property) Response area to get (resulting answer) Response area
(6 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Distribute to get
Combine like terms to get Response area
Use the (choose a property) Response area to get (resulting equation) Response area
Use the (choose a property) Response area to get (resulting answer) Response area
2(x - 3) + 21 = -3
Distribute to get:
2x - 6 + 21 = -3
Combine like terms to get:
2x + 15 = -3
Use the addition property of equality to get:
2x = -18
Use the division property of equality to get:
x = -9
Distribute to get:
2x - 6 + 21 = -3
Combine like terms to get:
2x + 15 = -3
Use the addition property of equality to get:
2x = -18
Use the division property of equality to get:
x = -9
ax−44<15
Let's solve the inequality:
ax - 44 < 15
Adding 44 to both sides:
ax < 59
Dividing both sides by a:
x < 59/a
ax - 44 < 15
Adding 44 to both sides:
ax < 59
Dividing both sides by a:
x < 59/a
check you answer
Apologies for the previous incorrect response.
Let's solve the inequality correctly this time:
ax - 44 < 15
Adding 44 to both sides:
ax < 59
Dividing both sides by a (assuming a is positive):
x < 59/a
To check this answer, we need to know the value of a. Please provide the value of a so we can verify the solution.
Let's solve the inequality correctly this time:
ax - 44 < 15
Adding 44 to both sides:
ax < 59
Dividing both sides by a (assuming a is positive):
x < 59/a
To check this answer, we need to know the value of a. Please provide the value of a so we can verify the solution.
ax+15=44
To solve the equation ax + 15 = 44, we will isolate the variable.
Subtract 15 from both sides to get:
ax + 15 - 15 = 44 - 15
This simplifies to:
ax = 29
To solve for x, divide both sides by a (assuming a is not equal to zero):
ax/a = 29/a
Simplifying further:
x = 29/a
So the solution to the equation is x = 29/a.
Subtract 15 from both sides to get:
ax + 15 - 15 = 44 - 15
This simplifies to:
ax = 29
To solve for x, divide both sides by a (assuming a is not equal to zero):
ax/a = 29/a
Simplifying further:
x = 29/a
So the solution to the equation is x = 29/a.
19. The base of a triangle is four less than three times the height. The area of the triangle is 38 square centimeters. A=(b×h)2
(3 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
An expression for the base of the triangle: Response area
Equation for the area of the triangle, substituting in for the base: Response area
The first step in solving for h: Response area
(3 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
An expression for the base of the triangle: Response area
Equation for the area of the triangle, substituting in for the base: Response area
The first step in solving for h: Response area
Let's solve the problem step by step.
Given:
The base of a triangle is four less than three times the height.
The area of the triangle is 38 square centimeters.
1. An expression for the base of the triangle:
Let h be the height of the triangle.
The expression for the base would be: 3h - 4.
2. Equation for the area of the triangle, substituting in for the base:
Using the formula A = (base * height) / 2, we can substitute the base expression into the equation.
The equation for the area of the triangle becomes: (3h - 4) * h / 2 = 38.
3. The first step in solving for h:
We can start by simplifying the equation.
Multiplying both sides of the equation by 2 to eliminate the fraction, we get: (3h - 4) * h = 76.
Please let me know if there's anything specific you would like to solve next.
Given:
The base of a triangle is four less than three times the height.
The area of the triangle is 38 square centimeters.
1. An expression for the base of the triangle:
Let h be the height of the triangle.
The expression for the base would be: 3h - 4.
2. Equation for the area of the triangle, substituting in for the base:
Using the formula A = (base * height) / 2, we can substitute the base expression into the equation.
The equation for the area of the triangle becomes: (3h - 4) * h / 2 = 38.
3. The first step in solving for h:
We can start by simplifying the equation.
Multiplying both sides of the equation by 2 to eliminate the fraction, we get: (3h - 4) * h = 76.
Please let me know if there's anything specific you would like to solve next.
20. Solve the equation for y: 3x+5y=60
(1 point)
Responses
y=57x5
y is equal to 57 x over 5
y=60+3x5
y is equal to 60 plus 3 x over 5
y=60−3x
y is equal to 60 minus 3 x
y=−35x+12
(1 point)
Responses
y=57x5
y is equal to 57 x over 5
y=60+3x5
y is equal to 60 plus 3 x over 5
y=60−3x
y is equal to 60 minus 3 x
y=−35x+12
To solve the equation 3x + 5y = 60 for y, we need to isolate the variable y.
First, let's move the 3x term to the other side of the equation by subtracting 3x from both sides:
5y = 60 - 3x
Next, let's divide both sides by 5 to solve for y:
y = (60 - 3x) / 5
So, the correct response is:
y = (60 - 3x) / 5
First, let's move the 3x term to the other side of the equation by subtracting 3x from both sides:
5y = 60 - 3x
Next, let's divide both sides by 5 to solve for y:
y = (60 - 3x) / 5
So, the correct response is:
y = (60 - 3x) / 5