A submarine was the depth of 106.3 feet below sea level. After 5 hours the submarine was 481.2 feet below sea level. How far did the submarine travel

1 answer

To find the distance the submarine traveled, we need to subtract the initial depth from the final depth.

Final depth: 481.2 feet below sea level
Initial depth: 106.3 feet below sea level

Distance traveled = Final depth - Initial depth
Distance traveled = 481.2 - 106.3
Distance traveled = 374.9 feet

Therefore, the submarine traveled a distance of 374.9 feet below sea level.