To simplify 9^-3 × 9^9 in exponential form, we can use the rule that states when multiplying two numbers with the same base, we add their exponents.
Therefore, 9^-3 × 9^9 can be written as 9^(-3+9).
Simplifying the exponents, we get 9^(6).
Thus, 9^-3 × 9^9 can be written in exponential form as 9^6.
Simplify 9^-3×9^9 in exponential form
15 answers
Simplify x³\cdotx
To simplify x³⋅x, we can use the rule that states that when multiplying two numbers with the same base, we add their exponents.
Therefore, x³⋅x can be written as x^(3+1).
Simplifying the exponents, we get x^4.
Thus, x³⋅x can be simplified to x^4.
Therefore, x³⋅x can be written as x^(3+1).
Simplifying the exponents, we get x^4.
Thus, x³⋅x can be simplified to x^4.
Simplify 4^13×4^-9 in exponential form
To simplify 4^13 × 4^-9 in exponential form, we can use the rule that states when multiplying two numbers with the same base, we add their exponents.
Therefore, 4^13 × 4^-9 can be written as 4^(13+(-9)).
Simplifying the exponents, we get 4^4.
Thus, 4^13 × 4^-9 can be written in exponential form as 4^4.
Therefore, 4^13 × 4^-9 can be written as 4^(13+(-9)).
Simplifying the exponents, we get 4^4.
Thus, 4^13 × 4^-9 can be written in exponential form as 4^4.
Simplify 7¹⁵×7 in exponential form
To simplify 7¹⁵ × 7 in exponential form, we can add the exponents since the bases are the same.
Therefore, 7¹⁵ × 7 can be written as 7^(15+1).
Simplifying the exponents, we get 7^16.
Thus, 7¹⁵ × 7 can be simplified to 7^16 in exponential form.
Therefore, 7¹⁵ × 7 can be written as 7^(15+1).
Simplifying the exponents, we get 7^16.
Thus, 7¹⁵ × 7 can be simplified to 7^16 in exponential form.
Find the missing value for y^-2\cdoty^?=y^11
?=
?=
To find the missing value for y^-2⋅y^?=y^11, we can use the rule that states when multiplying two numbers with the same base, we add their exponents.
Therefore, y^-2⋅y^? can be written as y^(-2+?) and is equal to y^11.
To solve for ?, we can equate the exponents:
-2 + ? = 11
Adding 2 to both sides, we get:
? = 13
Thus, the missing value in y^-2⋅y^?=y^11 is ?=13.
Therefore, y^-2⋅y^? can be written as y^(-2+?) and is equal to y^11.
To solve for ?, we can equate the exponents:
-2 + ? = 11
Adding 2 to both sides, we get:
? = 13
Thus, the missing value in y^-2⋅y^?=y^11 is ?=13.
Simplify 4⁶×4⁹ in exponential form
To simplify 4⁶ × 4⁹ in exponential form, we can use the rule that states when multiplying two numbers with the same base, we add their exponents.
Therefore, 4⁶ × 4⁹ can be written as 4^(6+9).
Simplifying the exponents, we get 4^15.
Thus, 4⁶ × 4⁹ can be written in exponential form as 4^15.
Therefore, 4⁶ × 4⁹ can be written as 4^(6+9).
Simplifying the exponents, we get 4^15.
Thus, 4⁶ × 4⁹ can be written in exponential form as 4^15.
Simplify z^-15\cdotz^15
To simplify z^-15 × z^15, we can use the rule that states when multiplying two numbers with the same base, we add their exponents.
Therefore, z^-15 × z^15 can be written as z^(-15+15).
Simplifying the exponents, we get z^0.
Any number (except for 0) raised to the power of 0 is equal to 1.
Thus, z^-15 × z^15 can be simplified to 1.
Therefore, z^-15 × z^15 can be written as z^(-15+15).
Simplifying the exponents, we get z^0.
Any number (except for 0) raised to the power of 0 is equal to 1.
Thus, z^-15 × z^15 can be simplified to 1.
Z^-5\cdotz^15
To simplify z^-5 × z^15, we can use the rule that states when multiplying two numbers with the same base, we add their exponents.
Therefore, z^-5 × z^15 can be written as z^(-5+15).
Simplifying the exponents, we get z^10.
Thus, z^-5 × z^15 can be simplified to z^10.
Therefore, z^-5 × z^15 can be written as z^(-5+15).
Simplifying the exponents, we get z^10.
Thus, z^-5 × z^15 can be simplified to z^10.