The ages (in years) of 10 randomly selected individuals are 24, 15, 18, 30, 32, 40, 22, 27, 33, and 35. Form a new dataset by replacing the maximum age with 50. In years, how much higher is the mean of the new dataset than the mean of the original dataset?(1 point)

Question

year(s)

Answer 1

The original dataset has a mean of (24 + 15 + 18 + 30 + 32 + 40 + 22 + 27 + 33 + 35)/10 = 29.6 years.

The new dataset has a mean of (24 + 15 + 18 + 30 + 32 + 40 + 22 + 27 + 33 + 50)/10 = 28.1 years.

The mean of the new dataset is 29.6 - 28.1 = <<29.6-28.1=1.5>>1.5 years higher than the mean of the original dataset. Answer: \boxed{1.5}.

Answer 2

Use the table to answer the question.

Group 1 20 22 14 25 18 33 28 35 43 18
Group 2 16 24 30 26 28 32 34 23 25 33
The math scores of the two groups of students are summarized in the table.
Which group of scores is more dispersed than the other?

(1 point)

Answer 3

To determine which group of scores is more dispersed, we can compare the measures of dispersion such as the range, interquartile range, or standard deviation.

However, without the specific values of each score, we cannot calculate these measures and directly compare the dispersion between the two groups.

Therefore, without more information, we cannot determine which group of scores is more dispersed.

Answer 4

The ages (in years) of 10 randomly selected individuals are 24, 15, 18, 30, 32, 40, 22, 27, 33, and 35. Form a new dataset by replacing the maximum age with 50. In years, how much higher is the mean of the new dataset than the mean of the original dataset?(1 point).
year(s)