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Solve for each of the formulas for the indicated variable:

P = 2L + 2W for W

9 answers

To solve for W, we need to isolate the variable W on one side of the equation.

P = 2L + 2W

First, subtract 2L from both sides to get:
P - 2L = 2W

Then, divide both sides by 2 to solve for W:
(P - 2L)/2 = W

Therefore, our final solution is:
W = (P - 2L)/2
Solve for each of the formulas for the indicated variable:
ax + b = 0 for x
To solve for x in the equation ax + b = 0, we need to isolate x on one side of the equation.

Subtract b from both sides:
ax = -b

Divide both sides by a to solve for x:
x = -b/a

Therefore, our final solution is:
x = -b/a
the indicated variable:
V=LWH for H
To solve for H in the formula V = LWH, we need to isolate H on one side of the equation.

Divide both sides of the equation by LW:
V / (LW) = H

Therefore, the solution for H is:
H = V / (LW)
the indicated variable:
y=mx + b for x
To solve for x in the formula y = mx + b, we need to isolate x on one side of the equation.

First, subtract b from both sides:
y - b = mx

Next, divide both sides by m:
(y - b) / m = x

Therefore, the solution for x is:
x = (y - b) / m
Solve for each of the formulas for the indicated variable:

If the perimeter of a rectangle is 60ft and its length is 18ft, find its width. (see formula in number 1)
The formula for the perimeter of a rectangle is given by P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.

In this case, the perimeter is given as 60ft and the length is given as 18ft. Let's solve for the width.

Substituting the given values into the formula, we have:
60ft = 2(18ft) + 2W

Simplifying the equation, we get:
60ft = 36ft + 2W

Subtracting 36ft from both sides of the equation, we have:
24ft = 2W

Dividing both sides of the equation by 2, we get:
W = 12ft

Therefore, the width of the rectangle is 12ft.