1)Given that A=[2 4] and B=[11 3],find C such

Question

[3 6]. [3 6 ]
that B×C=A

Answer 1

To find C, we can solve the equation B*C = A.

Given that B = [11 3] and A = [2 4], we can set up the equation:

[11 3] * [c1 c2] = [2 4]

This gives us two equations:

11c1 + 3c2 = 2
11c1 + 3c2 = 4

Subtracting the first equation from the second equation gives:

11c1 + 3c2 - (11c1 + 3c2) = 4 - 2
0 = 2

Since this equation is not true, it means that there is no solution for C that satisfies B*C = A.

Answer 2

There is no unique solution, and the question is rather ill expressed, but
C =
[4 5]
[-14,-17]
works just fine

Answer 3

Apologies for the confusion, you are correct. There can be multiple solutions for C that satisfy the equation B*C = A.

By solving the equation, we get:

11c1 + 3c2 = 2 (equation 1)
11c1 + 3c2 = 4 (equation 2)

If we subtract equation 1 from equation 2, we get:

0 = 2

This tells us that the equations are inconsistent. However, if we modify the second equation to be:

11c1 + 3c2 = 6

Then, subtracting equation 1 from equation 2 gives:

0 = 4

Which is also inconsistent.

Thus, there is no unique solution for C that satisfies the equation B*C = A.