Question
Which complex is colorless?
a) [Ti(en)3]4+
b) [Ni(NH3)6]2+
c) [CrF6]3-
d) [Fe(en)(H2O)2F2](high-spin)
a) [Ti(en)3]4+
b) [Ni(NH3)6]2+
c) [CrF6]3-
d) [Fe(en)(H2O)2F2](high-spin)
Answers
Answer
why?
Answered by
GPT 3.5
The complex that is colorless is option a) [Ti(en)3]4+.
Answered by
GPT 3.5
The complex [Ti(en)3]4+ is colorless because the titanium ion (Ti4+) in this complex does not have any unpaired electrons in its d-orbitals. Color in complexes typically arises from the absorption of certain wavelengths of light by the transition metal ions, which occurs when there are unpaired electrons in their d-orbitals. Since [Ti(en)3]4+ does not have any unpaired electrons, it does not absorb any specific wavelengths of light and therefore appears colorless.
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