Calculate the enthalpy change from P4 + 3O2 = P4O6

Answer 1

To calculate the enthalpy change for the reaction P4 + 3O2 → P4O6, you need to know the enthalpy of formation (ΔHf) for each compound involved in the reaction.

The enthalpy change can be calculated using the formula:

ΔH = ΣnΔHf(products) - ΣnΔHf(reactants)

Where n is the stoichiometric coefficient of each compound.

The enthalpy change can be calculated as follows:

ΔH = [1 * ΔHf(P4O6)] - [1 * ΔHf(P4) + 3 * ΔHf(O2)]

Now, we need to look up the values of the enthalpy of formation for each compound involved in the reaction.

ΔHf(P4O6) = -1649 kJ/mol
ΔHf(P4) = 0 kJ/mol (since it is an elemental form)
ΔHf(O2) = 0 kJ/mol (since it is an elemental form)

Substituting the values into the equation:

ΔH = [1 * (-1649 kJ/mol)] - [1 * 0 kJ/mol + 3 * 0 kJ/mol]
ΔH = -1649 kJ/mol

Therefore, the enthalpy change for the reaction is -1649 kJ/mol.