To determine how many digits are in the repeating cycle of a rational number expressed in decimal form, we can look at the remainder when the numerator is divided by the denominator.
In this case, we have the rational number $\frac{1727}{1}$. When we divide 1727 by 1, we get a quotient of 1727 and a remainder of 0. Since the remainder is 0, there is no repeating cycle. Therefore, there are 0 digits in the repeating cycle of 1727.
Answer: \boxed{0}.
Rational Numbers in Different Forms Practice
Math 8 Q1 (Pre-Algebra) / The Number System
How many digits are in the repeating cycle of 1727?(1 point)
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5 answers
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Apologies for the incorrect response. Let's try solving it correctly.
To find the repeating cycle in the decimal representation of a fraction, we can perform long division.
Let's divide 1727 by 1:
1727
_____________
1 | 1727
We see that 1 is a factor of 1727. So, the decimal representation of $\frac{1727}{1}$ is 1727.
Since 1727 has no decimal part, there is no repeating cycle.
Therefore, the number of digits in the repeating cycle of 1727 is \boxed{0}.
To find the repeating cycle in the decimal representation of a fraction, we can perform long division.
Let's divide 1727 by 1:
1727
_____________
1 | 1727
We see that 1 is a factor of 1727. So, the decimal representation of $\frac{1727}{1}$ is 1727.
Since 1727 has no decimal part, there is no repeating cycle.
Therefore, the number of digits in the repeating cycle of 1727 is \boxed{0}.
How many digits in 17/27