An isosceles triangle has at least two congruent sides. The perimeter of a certain isosceles triangle is at most 12 in. The length of each of the two congruent sides is 5 in. What are the possible lengths of the remaining side?

Answer 1

Let the length of the remaining side be $x$. Given that the perimeter of the triangle is at most 12 in., we have $5+5+x\leq 12$. Solving, we find $x\leq 2$.

Since the remaining side cannot be longer than 2 in., the possible lengths of the remaining side are $\boxed{0 \text{ in.}, 2 \text{ in.}}$.