To find the total mass of the products in the chemical reaction, we need to use the balanced equation and the molar masses of the substances involved.
The balanced equation given is:
CaCO3 → CO2 + CaO
To find the total mass of the products, we first need to calculate the molar masses of CO2 and CaO.
The molar mass of CO2 (carbon dioxide) is found by adding up the atomic masses of carbon (C) and oxygen (O):
C: 12.01 g/mol
O: 16.00 g/mol (there are two oxygen atoms in CO2)
Molar mass of carbon dioxide (CO2):
12.01 g/mol + 16.00 g/mol + 16.00 g/mol = 44.01 g/mol
The molar mass of CaO (calcium oxide) is found by adding up the atomic masses of calcium (Ca) and oxygen (O):
Ca: 40.08 g/mol
O: 16.00 g/mol (there is one oxygen atom in CaO)
Molar mass of calcium oxide (CaO):
40.08 g/mol + 16.00 g/mol = 56.08 g/mol
Now, we can calculate the total mass of the products using the molar masses and stoichiometry:
The molar ratio between CaCO3 and CO2 in the balanced equation is 1:1. Therefore, the molar mass of CO2 is equal to the molar mass of CaCO3.
Given that the mass of CaCO3 is 30 grams, the mass of CO2 produced will also be 30 grams.
Next, we can determine the mass of CaO produced. The molar ratio between CaCO3 and CaO is 1:1. This means that 1 mole of CaCO3 produces 1 mole of CaO.
The molar mass of CaCO3 is 100.09 g/mol (40.08 g/mol for Ca + 12.01 g/mol for C + 3(16.00 g/mol) for O).
Using the molar mass and the given mass of CaCO3 (30 grams), we can determine the number of moles of CaCO3:
30 g / 100.09 g/mol = 0.2999 mol (approximately)
Since the molar ratio is 1:1 between CaCO3 and CaO, the mass of CaO produced will also be approximately 30 grams (0.2999 mol × 56.08 g/mol).
Therefore, the total mass of the products in the chemical reaction is approximately 30 grams of CO2 and 30 grams of CaO.
The correct response is "30 grams".