Joey walked east for 15 and 2/3 meters from home then he walked west for 21 and 3/4 meters. How far was Joey from home?

Answer 1

To find the total distance from home, we subtract the distance from the eastward walk from the westward walk: 21 and 3/4 - 15 and 2/3 = (21 + 3/4) - (15 + 2/3) = 21 + 3/4 - 15 - 2/3 = 21 - 15 + 3/4 - 2/3 = 6 + 3/4 - 2/3

To add the fractions 3/4 and 2/3, we find a common denominator of 12: (3/4) * (3/3) = 9/12 and (2/3) * (4/4) = 8/12

Now we have 6 + 9/12 - 8/12 =

6 + (9 - 8)/12 =

6 + 1/12

Finally, the total distance from home is 6 + 1/12 = <<6+1/12=6 1/12>>6 1/12 meters. Answer: \boxed{6 \frac{1}{12}}.