Question

The water level of a river is below normal levels. Its water level is at 1 1/2
meters below sea level. During the summer, the river drops another 2 1/3
meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level. Account for this in your answer.

Answer 1

nuh uh

Answer 2

no :/

Answer 3

To find the water level at the end of summer, we need to add the initial water level (1 1/2 meters below sea level) and the drop during summer (2 1/3 meters below sea level).

First, let's convert the mixed fractions to improper fractions.
1 1/2 can be written as (1 * 2 + 1) / 2 = 3/2 meters below sea level.
2 1/3 can be written as (2 * 3 + 1) / 3 = 7/3 meters below sea level.

Adding the two fractions gives us (3/2) + (7/3).
To add fractions, we need to find a common denominator, which in this case is 6.
(3/2) can be rewritten as (3 * 3) / (2 * 3) = 9/6 meters below sea level.
(7/3) can be rewritten as (7 * 2) / (3 * 2) = 14/6 meters below sea level.

Now that we have the fractions with a common denominator, we can add them: (9/6) + (14/6) = 23/6.

Therefore, the water level at the end of summer is 23/6 meters below sea level.

Answer 4

My apologies, let's redo the calculation.

The initial water level is 1 1/2 meters below sea level, which can be written as (3/2) meters below sea level.

During the summer, the river drops another 2 1/3 meters below sea level, which can be written as (7/3) meters below sea level.

To find the water level at the end of summer, we need to subtract the drop during summer from the initial water level:

(3/2) - (7/3)

To subtract fractions, we need a common denominator, which in this case is 6.

(3/2) can be rewritten as (9/6) meters below sea level.

(7/3) can be rewritten as (14/6) meters below sea level.

Now, we subtract: (9/6) - (14/6) = (-5/6)

Therefore, the water level at the end of summer is 5/6 meters below sea level.

Answer 5

Apologies for the confusion earlier. Let's recalculate the water level at the end of summer.

The initial water level is 1 1/2 meters below sea level, which is equal to (3/2) meters below sea level.

During the summer, the river drops another 2 1/3 meters below sea level, which is equal to (7/3) meters below sea level.

To find the total drop in the water level, we need to add the initial drop and the drop during summer:

(3/2) + (7/3)

Unfortunately, we cannot add these fractions directly because they have different denominators.

To find a common denominator, we multiply the denominators together: 2 * 3 = 6.

Now, let's convert both fractions to have a denominator of 6:

(3/2) * (3/3) = 9/6

(7/3) * (2/2) = 14/6

Now that the fractions have a common denominator, we can add them:

9/6 + 14/6 = 23/6

Therefore, the water level at the end of summer is 23/6 meters below sea level.