Asked by kkjhjkh
Suppose X is a random variable whose CDF is given by
F(x) = 0, X<0
X^3, 0<X<1;
1, 1<X
Then the mean for this random variable is:
I don't understand how to do CDF (cumulitive distribution function) or how to get the mean of it. Thank You!
F(x) = 0, X<0
X^3, 0<X<1;
1, 1<X
Then the mean for this random variable is:
I don't understand how to do CDF (cumulitive distribution function) or how to get the mean of it. Thank You!
Answers
Answered by
drwls
The average or mean of a distribution F(x) is the integral of F(x)dx
(which in this case = 1/4 when the limits are 0 and 1) divided by the width of the interval (which in this case = 1). So the answer is 1/4.
(which in this case = 1/4 when the limits are 0 and 1) divided by the width of the interval (which in this case = 1). So the answer is 1/4.