Question

what is the mass of an object that stretch s the spring 35 cm long?(take g=0.01N/
g)

Answer 1

To determine the mass of an object that stretches a spring 35 cm long, you need to know the spring constant (k) of the spring. The spring constant represents the stiffness of the spring and is typically given in units of Newton per meter (N/m).

Once you have the spring constant, you can use Hooke's law to calculate the force exerted by the spring when it is stretched a certain length. Hooke's law states that the force (F) exerted by a spring is proportional to the displacement (x) from its equilibrium position and is given by the equation F = kx.

In this case, the displacement (x) is given as 35 cm, which is equal to 0.35 meters. And the force (F) can be calculated using the formula F = kx.

Now, you are given the value of the acceleration due to gravity (g) as 0.01 N/g. Since g is acting vertically downwards, and the force exerted by the spring is acting in the opposite direction, we need to include a negative sign in the equation.

So, the equation becomes -0.01 kg * 9.8 m/s^2 = k * 0.35 m.

Simplifying the equation, we have -0.098 N = k * 0.35 m.

Now, divide both sides of the equation by 0.35 m to solve for k:

k = -0.098 N / 0.35 m

Once you know the spring constant (k), you can calculate the mass (m) of the object using the formula:

k = m * g

Rearranging the formula to solve for m, we have:

m = k / g

Now, substitute the values of k and g into the formula to calculate the mass of the object:

m = (-0.098 N / 0.35 m) / 0.01 N/g

m = -0.098 kg

Note: The negative sign indicates that the force exerted by the spring opposes the force of gravity, so the mass is considered negative in this case.