Asked by Junko Enoshima
I want to compare the distances of two different stores from home. What key word shows that you are finding the difference between rational numbers.
home
different
compare
distanceumbers?
home
different
compare
distanceumbers?
Answers
Answered by
Junko Enoshima
I want to compare the distances of two different stores from home. What key word shows that you are finding the difference between rational numbers.
home
different
compare
distance
home
different
compare
distance
Answered by
Junko Enoshima
Mark had a balance of −$11 in his checking account. The bank charged a $25 fee. What is the balance in the account?
Answered by
Junko Enoshima
Mark had a balance of −$11 in his checking account. The bank charged a $25 fee. What is the balance in the account? previous answer was wrong
Answered by
Junko Enoshima
The water level of a river is below normal levels. Its water level is at 1 1/2 meters below sea level. During the summer, the river drops another 2 1/3 meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level. Account for this in your answer.
Answered by
Junko Enoshima
The water level of a river is below normal levels. Its water level is at 1 1/2 meters below sea level. During the summer, the river drops another 2 1/3 meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level.
previous answer was wrong):
previous answer was wrong):
Answered by
Junko Enoshima
wrong give the right answer or i will fail
Answered by
Junko Enoshima
wrong
Answered by
Junko Enoshima
wrong again
Answered by
Junko Enoshima
you are bad at math
Answered by
Junko Enoshima
wrong im gonna fail because of you
Answered by
Junko Enoshima
The water level of a river is below normal levels. Its water level is at 112
meters below sea level. During the summer, the river drops another 213
meters below sea level. What is the water level at the end of summer?
Answered by
Junko Enoshima
The water level of a river is below normal levels. Its water level is at 1 1/2
meters below sea level. During the summer, the river drops another 2 1/3
meters below sea level. What is the water level at the end of summer?
meters below sea level. During the summer, the river drops another 2 1/3
meters below sea level. What is the water level at the end of summer?
Answered by
Junko Enoshima
1 1/2-2 1/3
Answered by
Junko Enoshima
The rainfall in a town was 2.3 inches above normal in June. In July, the rainfall was 1.2 inches below normal. What was the difference in rainfall between the months?
Answered by
Junko Enoshima
A submarine was at a depth of 106.3 feet below sea level. After 5 hours, the submarine was at 481.2 feet below sea level. How far did the submarine travel?
Answered by
GPT 3.5
rational
Answered by
GPT 3.5
difference
Answered by
GPT 3.5
To find the balance in Mark's account after the fee, we need to add the fee amount to the current balance.
Balance + Fee = New Balance
In this case, Mark's balance is −$11 and the fee is $25. So,
−$11 + $25 = $14
Therefore, the new balance in Mark's account is $14.
Balance + Fee = New Balance
In this case, Mark's balance is −$11 and the fee is $25. So,
−$11 + $25 = $14
Therefore, the new balance in Mark's account is $14.
Answered by
GPT 3.5
Apologies for the incorrect previous answer. To find the new balance in Mark's account, we need to subtract the fee amount from the current balance because the fee is a debit or withdrawal.
Balance - Fee = New Balance
In this case, Mark's balance is −$11, and the fee is $25.
−$11 - $25 = −$36
Therefore, the new balance in Mark's account is −$36.
Balance - Fee = New Balance
In this case, Mark's balance is −$11, and the fee is $25.
−$11 - $25 = −$36
Therefore, the new balance in Mark's account is −$36.
Answered by
GPT 3.5
To find the water level at the end of summer, we need to add the additional drop in the river's level to its initial level.
Initial level: 1 1/2 meters below sea level
Additional drop during summer: 2 1/3 meters below sea level
Let's convert the fractions to a common denominator, which is 6:
Initial level: 9/6 meters below sea level
Additional drop during summer: 15/6 meters below sea level
Now, we can add the two values together:
9/6 + 15/6 = 24/6 = 4 meters below sea level
Therefore, at the end of summer, the water level of the river is 4 meters below sea level.
Initial level: 1 1/2 meters below sea level
Additional drop during summer: 2 1/3 meters below sea level
Let's convert the fractions to a common denominator, which is 6:
Initial level: 9/6 meters below sea level
Additional drop during summer: 15/6 meters below sea level
Now, we can add the two values together:
9/6 + 15/6 = 24/6 = 4 meters below sea level
Therefore, at the end of summer, the water level of the river is 4 meters below sea level.
Answered by
GPT 3.5
Apologies for the incorrect previous answer. Let's calculate the correct water level at the end of summer.
Initial level: 1 1/2 meters below sea level, which can be written as 3/2 meters below sea level.
Additional drop during summer: 2 1/3 meters below sea level, which can be written as 7/3 meters below sea level.
To find the total drop in the water level, we need to add the initial level and the additional drop:
3/2 + 7/3
To add these fractions, we need to find a common denominator:
3/2 can be written as 9/6
7/3 can be written as 14/6
Now we can add the fractions:
9/6 + 14/6 = 23/6
Therefore, at the end of summer, the water level of the river is 23/6 meters below sea level.
Initial level: 1 1/2 meters below sea level, which can be written as 3/2 meters below sea level.
Additional drop during summer: 2 1/3 meters below sea level, which can be written as 7/3 meters below sea level.
To find the total drop in the water level, we need to add the initial level and the additional drop:
3/2 + 7/3
To add these fractions, we need to find a common denominator:
3/2 can be written as 9/6
7/3 can be written as 14/6
Now we can add the fractions:
9/6 + 14/6 = 23/6
Therefore, at the end of summer, the water level of the river is 23/6 meters below sea level.
Answered by
GPT 3.5
Apologies for the confusion. Let's recalculate the water level at the end of summer correctly.
Initial level: 1 1/2 meters below sea level, which can be written as 3/2 meters below sea level.
Additional drop during summer: 2 1/3 meters below sea level, which can be written as 7/3 meters below sea level.
To find the total drop in the water level, we need to add the initial level and the additional drop:
3/2 + 7/3
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(3/2)*(3/3) + (7/3)*(2/2)
= 9/6 + 14/6
= 23/6
Therefore, at the end of summer, the water level of the river is 23/6 meters below sea level.
Initial level: 1 1/2 meters below sea level, which can be written as 3/2 meters below sea level.
Additional drop during summer: 2 1/3 meters below sea level, which can be written as 7/3 meters below sea level.
To find the total drop in the water level, we need to add the initial level and the additional drop:
3/2 + 7/3
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(3/2)*(3/3) + (7/3)*(2/2)
= 9/6 + 14/6
= 23/6
Therefore, at the end of summer, the water level of the river is 23/6 meters below sea level.
Answered by
GPT 3.5
Apologies for the confusion. Let's recalculate the water level at the end of summer correctly.
Initial level: 1 1/2 meters below sea level, which can be written as -3/2 meters (negative because it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -7/3 meters (negative because it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
Initial level: 1 1/2 meters below sea level, which can be written as -3/2 meters (negative because it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -7/3 meters (negative because it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
Answered by
GPT 3.5
Apologies for the previous incorrect answers. Let's recalculate the water level at the end of summer correctly.
Initial level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (negative because it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (negative because it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-1 1/2 + (-2 1/3)
To add these mixed numbers, we can convert them to improper fractions:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
Initial level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (negative because it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (negative because it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-1 1/2 + (-2 1/3)
To add these mixed numbers, we can convert them to improper fractions:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
Answered by
GPT 3.5
I apologize if my previous responses were incorrect or confusing. Let's correctly calculate the water level at the end of summer.
Initial level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (since it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (since it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-1 1/2 + (-2 1/3)
To add these mixed numbers, we'll convert them to improper fractions:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
Initial level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (since it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (since it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-1 1/2 + (-2 1/3)
To add these mixed numbers, we'll convert them to improper fractions:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
Answered by
GPT 3.5
I apologize for any confusion or frustration caused. Let's make sure to calculate the water level at the end of summer correctly this time.
Initial level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (since it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (since it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-1 1/2 + (-2 1/3)
To add these mixed numbers, we'll convert them to improper fractions:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
If you have any further questions or need additional assistance, please let me know.
Initial level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (since it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (since it is below sea level).
To find the total drop in the water level, we need to add the initial level and the additional drop:
-1 1/2 + (-2 1/3)
To add these mixed numbers, we'll convert them to improper fractions:
-3/2 + (-7/3)
To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) + (-7/3)*(2/2)
= -9/6 + (-14/6)
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
If you have any further questions or need additional assistance, please let me know.
Answered by
GPT 3.5
To find the water level at the end of summer, we need to subtract the additional drop during the summer from the initial water level.
Initial water level: 112 meters below sea level
Additional drop during summer: 213 meters below sea level
To calculate the water level at the end of summer:
112 meters below sea level - 213 meters below sea level
To subtract these values, we can combine them as negative numbers:
-112 - 213
When we subtract, we disregard the negative sign and subtract the absolute values:
112 + 213 = 325
Therefore, at the end of summer, the water level of the river is 325 meters below sea level.
Initial water level: 112 meters below sea level
Additional drop during summer: 213 meters below sea level
To calculate the water level at the end of summer:
112 meters below sea level - 213 meters below sea level
To subtract these values, we can combine them as negative numbers:
-112 - 213
When we subtract, we disregard the negative sign and subtract the absolute values:
112 + 213 = 325
Therefore, at the end of summer, the water level of the river is 325 meters below sea level.
Answered by
GPT 3.5
To find the water level at the end of summer, we need to subtract the additional drop during the summer from the initial water level.
Initial water level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (since it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (since it is below sea level).
To calculate the water level at the end of summer:
-1 1/2 - 2 1/3
To subtract these mixed numbers, we'll convert them to improper fractions:
-3/2 - 7/3
To simplify the subtraction, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) - (7/3)*(2/2)
= -9/6 - 14/6
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
If you have any further questions, please let me know.
Initial water level: 1 1/2 meters below sea level, which can be written as -1 1/2 meters (since it is below sea level).
Additional drop during summer: 2 1/3 meters below sea level, which can be written as -2 1/3 meters (since it is below sea level).
To calculate the water level at the end of summer:
-1 1/2 - 2 1/3
To subtract these mixed numbers, we'll convert them to improper fractions:
-3/2 - 7/3
To simplify the subtraction, we need to find a common denominator. The least common multiple of 2 and 3 is 6:
(-3/2)*(3/3) - (7/3)*(2/2)
= -9/6 - 14/6
= -23/6
Therefore, at the end of summer, the water level of the river is -23/6 meters below sea level.
If you have any further questions, please let me know.
Answered by
GPT 3.5
To subtract 2 1/3 from 1 1/2, we need to find a common denominator:
1 1/2 = 3/2
2 1/3 = 7/3
Now subtract the fractions:
3/2 - 7/3
To do this, we need to find a common denominator which is 6:
(3/2)*(3/3) - (7/3)*(2/2)
= 9/6 - 14/6
Now subtract the numerators:
9/6 - 14/6 = -5/6
Therefore, 1 1/2 - 2 1/3 is equal to -5/6.
1 1/2 = 3/2
2 1/3 = 7/3
Now subtract the fractions:
3/2 - 7/3
To do this, we need to find a common denominator which is 6:
(3/2)*(3/3) - (7/3)*(2/2)
= 9/6 - 14/6
Now subtract the numerators:
9/6 - 14/6 = -5/6
Therefore, 1 1/2 - 2 1/3 is equal to -5/6.
Answered by
GPT 3.5
To find the difference in rainfall between June and July, we need to subtract the July rainfall from the June rainfall.
June rainfall: 2.3 inches above normal
July rainfall: 1.2 inches below normal
To calculate the difference in rainfall:
2.3 - (-1.2)
When subtracting a negative number, we can rewrite it as addition:
2.3 + 1.2
Adding these numbers gives us:
3.5
Therefore, the difference in rainfall between June and July is 3.5 inches.
June rainfall: 2.3 inches above normal
July rainfall: 1.2 inches below normal
To calculate the difference in rainfall:
2.3 - (-1.2)
When subtracting a negative number, we can rewrite it as addition:
2.3 + 1.2
Adding these numbers gives us:
3.5
Therefore, the difference in rainfall between June and July is 3.5 inches.
Answered by
GPT 3.5
To find the distance the submarine traveled, we need to calculate the difference between its initial depth and its final depth after 5 hours.
Initial depth: 106.3 feet below sea level
Final depth: 481.2 feet below sea level
To find the distance traveled:
Final depth - Initial depth = Distance traveled
481.2 - 106.3 = 374.9
Therefore, the submarine traveled a distance of 374.9 feet.
Initial depth: 106.3 feet below sea level
Final depth: 481.2 feet below sea level
To find the distance traveled:
Final depth - Initial depth = Distance traveled
481.2 - 106.3 = 374.9
Therefore, the submarine traveled a distance of 374.9 feet.
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