Asked by help
A gold wire 5.90m long and of diameter 0.890 mm carries a current of 1.21A.
A)Find the resistance of this wire.
B)Find the potential difference between its ends.
Can someone please help me I don't know how to answer these questions?
R=p(L/A) 1.21(5.90m/.890mm)
Am i setting this up right?
A)Find the resistance of this wire.
B)Find the potential difference between its ends.
Can someone please help me I don't know how to answer these questions?
R=p(L/A) 1.21(5.90m/.890mm)
Am i setting this up right?
Answers
Answered by
drwls
A) You will have to use the resistivity of gold (which you should look up) to get an answer. The current makes no difference.
R = (rho)* (L/A) is the correct formula.
Make sure you use consistent units, such as ohm-cm for rho, cm for length, and cm^2 for area. You did not do that in what you wrote.
B)Once you have computed R, V = I R
R = (rho)* (L/A) is the correct formula.
Make sure you use consistent units, such as ohm-cm for rho, cm for length, and cm^2 for area. You did not do that in what you wrote.
B)Once you have computed R, V = I R
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