Asked by Lola PLEASE HELP!
An 80- quarterback jumps straight up in the air right before throwing a 0.43- football horizontally at 15 . How fast will he be moving backward just after releasing the ball? Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far d will he move horizontally, assuming his speed is constant?
Answers
Answered by
Sagar Rana
2.4*10^-2 m
Answered by
Jenny Vo
I think just giving the person an answer is a little unhelpful.
m(Vf-Vi)=m(Vf-Vi)
80(Vf-0)=0.43(15-0)
80(Vf)=0.43(15)
80(Vf)=6.45
Vf=0.80625 m/s
0.080625 m/s * 0.03 m = 0.0241875 m the QB moves horizontally.
m(Vf-Vi)=m(Vf-Vi)
80(Vf-0)=0.43(15-0)
80(Vf)=0.43(15)
80(Vf)=6.45
Vf=0.80625 m/s
0.080625 m/s * 0.03 m = 0.0241875 m the QB moves horizontally.
Answered by
aardvarj
where did that 0.03 come from lol.
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