Asked by Steve
What change in coulombs, is required to deposit 0.301 g Cu(s) from a solution of Cu^2+(aq)
Answers
Answered by
drwls
Let's think it through step by step.
First convert 0.301g to moles of copper.
0.301 g /63.5 g/mole = 4.74*10^-3 moles.
Multiply that by 2 x (Avogadro's number) for the number of electrons.
Multiply what you get by the number of Coulombs per electron (1.602*10^-19).
I get 914 C
First convert 0.301g to moles of copper.
0.301 g /63.5 g/mole = 4.74*10^-3 moles.
Multiply that by 2 x (Avogadro's number) for the number of electrons.
Multiply what you get by the number of Coulombs per electron (1.602*10^-19).
I get 914 C
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.