Question
What change in coulombs, is required to deposit 0.301 g Cu(s) from a solution of Cu^2+(aq)
Answers
drwls
Let's think it through step by step.
First convert 0.301g to moles of copper.
0.301 g /63.5 g/mole = 4.74*10^-3 moles.
Multiply that by 2 x (Avogadro's number) for the number of electrons.
Multiply what you get by the number of Coulombs per electron (1.602*10^-19).
I get 914 C
First convert 0.301g to moles of copper.
0.301 g /63.5 g/mole = 4.74*10^-3 moles.
Multiply that by 2 x (Avogadro's number) for the number of electrons.
Multiply what you get by the number of Coulombs per electron (1.602*10^-19).
I get 914 C