To find the sum of -12 2/3 and -(-8 5/6), we first need to convert both mixed numbers to improper fractions.
-12 2/3 can be written as -38/3
-(-8 5/6) can be written as 8 5/6 since subtracting a negative number is the same as adding a positive number.
Now we can subtract the two fractions:
-38/3 - 8 5/6
To subtract the fractions, we need to find a common denominator. The least common multiple of 3 and 6 is 6, so we need to convert both fractions to have a denominator of 6.
-38/3 can be converted to -76/6 (multiply both numerator and denominator by 2).
8 5/6 can be converted to 53/6 by multiplying 8 by 6, which equals 48, and adding 5.
Now we can subtract the fractions:
-76/6 - 53/6
= (-76 - 53)/6
= -129/6
To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor, which is 3.
-129/6 = -43/2
Therefore, the answer is -43/2, which can be written as a mixed number as -21 1/2.
Use the additive inverse to find -12 2/3-(-8 5/6). Wrote the answer as a mixed number.
5 answers
Use the additive inverse to find −12 2/3−(−8 5/6)
. Write the answer as a mixed number.
. Write the answer as a mixed number.
To find the sum of −12 2/3 and −8 5/6 using the additive inverse, we can rewrite the subtraction as an addition problem by changing the sign of the second fraction:
−12 2/3 + 8 5/6
Next, we need to convert both mixed numbers to improper fractions:
−12 2/3 can be written as -38/3
8 5/6 can be written as 53/6
Now we can add the two fractions:
-38/3 + 53/6
To add the fractions, we need to find a common denominator. The least common multiple of 3 and 6 is 6, so we need to convert both fractions to have a denominator of 6.
-38/3 can be converted to -76/6 (multiply both numerator and denominator by 2).
Now we can add the fractions:
-76/6 + 53/6
= (-76 + 53)/6
= -23/6
To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor, which is 1 in this case.
-23/6 cannot be simplified further.
Therefore, the answer is -23/6, which can be written as a mixed number as -3 5/6.
−12 2/3 + 8 5/6
Next, we need to convert both mixed numbers to improper fractions:
−12 2/3 can be written as -38/3
8 5/6 can be written as 53/6
Now we can add the two fractions:
-38/3 + 53/6
To add the fractions, we need to find a common denominator. The least common multiple of 3 and 6 is 6, so we need to convert both fractions to have a denominator of 6.
-38/3 can be converted to -76/6 (multiply both numerator and denominator by 2).
Now we can add the fractions:
-76/6 + 53/6
= (-76 + 53)/6
= -23/6
To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor, which is 1 in this case.
-23/6 cannot be simplified further.
Therefore, the answer is -23/6, which can be written as a mixed number as -3 5/6.
Use the image to answer the question.
A number line ranges from negative 1 to 2 in increments of 1. A solid line with three dots is drawn along the number line, ranging from negative 1 to 2. The first dot is at Negative 1 and is labeled Jason’s friend’s house. dot two is at 0 and labeled Jason’s house. Dot 4 is at 2 and labeled Jason’s school.
Jason rides his bike home from school 2 miles. On his way back home from school, he passes his house to go to his friend's house, which is a mile farther. What is the total distance Jason traveled from school?
(1 point)
A number line ranges from negative 1 to 2 in increments of 1. A solid line with three dots is drawn along the number line, ranging from negative 1 to 2. The first dot is at Negative 1 and is labeled Jason’s friend’s house. dot two is at 0 and labeled Jason’s house. Dot 4 is at 2 and labeled Jason’s school.
Jason rides his bike home from school 2 miles. On his way back home from school, he passes his house to go to his friend's house, which is a mile farther. What is the total distance Jason traveled from school?
(1 point)
The total distance Jason traveled from school can be calculated by adding the distance from school to his house and the distance from his house to his friend's house.
Given that Jason rides his bike 2 miles from school to his house, and then passes his house to his friend's house, which is a mile farther, the total distance Jason traveled from school would be:
2 miles (distance from school to his house) + 1 mile (distance from his house to his friend's house) = 3 miles.
Given that Jason rides his bike 2 miles from school to his house, and then passes his house to his friend's house, which is a mile farther, the total distance Jason traveled from school would be:
2 miles (distance from school to his house) + 1 mile (distance from his house to his friend's house) = 3 miles.