Asked by claudia
What is the period of this function? - Maths?
y = 5+3sin (pie t divided by 3 + pie divided 2)
by definition the period is 2pi/k where k is the coefficient of the "angle"
so divide 2pi by pi/3 and simplify, hope you get 6
y = 5+3sin (pie t divided by 3 + pie divided 2)
by definition the period is 2pi/k where k is the coefficient of the "angle"
so divide 2pi by pi/3 and simplify, hope you get 6