Solve each of the following equations algebraically and check the solution.

Question

a 7+40=23
b
—2=4
3
12 = I)
c

Answer 1

a) 7 + 40 = 23

This equation is not true. There is no solution.

b) -2/3 = 4

To solve for the variable, we can multiply both sides of the equation by 3 to get rid of the denominator:

-2 = 4 * 3

Simplifying, we have:

-2 = 12

This equation is not true. There is no solution.

c) 12 = I

To solve for the variable, we want to isolate it on one side of the equation. In this case, the variable is already isolated. The solution is:

I = 12

To check the solution, substitute 12 back into the original equation:

12 = 12

This equation is true. The solution is correct.

Answer 2

For each of these equations, state the first operation you would apply to both sides to solve it.
2x+3=9`
b 4x-7=33
d 22 17)
C 5(a+3) 50

Answer 3

For the equation 2x + 3 = 9, the first operation to apply to both sides would be subtracting 3 from both sides. This will isolate the term with the variable on one side of the equation.

For the equation 4x - 7 = 33, the first operation to apply to both sides would be adding 7 to both sides to get rid of the negative constant term. This will isolate the term with the variable on one side of the equation.

For the equation 22 = 17, it is already solved. There is nothing to apply to both sides.

For the equation 5(a + 3) = 50, the first operation to apply to both sides would be dividing both sides by 5 to solve for the term within the parentheses.