Try the following but check me out.
I would rearrange the equation in the form of y = mx + b.
I believe that's
y = (1/3)x - (1/6).
The line perpendicular to that line has a slope of the negative reciprocal or -3 in this case.
Then use y = mx + b.
y = -3x + b
and substitute the point (10,-1) and solve for b.
What are you supposes to do to write the equation of a line that is perpendicular to the given line and that passes through the given point:
4x-12y=2; (10,-1)
2 answers
I got y=-3x+29. thanks
1 answer