A body of mass 400g is

whirled in a vertical of radius 2m
at a steady rate of 2rev/s. find its
centripetal force.
A. 160N
B. 102N
C. 320N
D. 252N

1 answer

The centripetal force can be found using the equation:

Centripetal force = mass * (velocity^2) / radius

First, we need to convert the mass to kilograms, so 400g = 0.4kg.

The radius is given as 2m.

The velocity can be calculated using the formula for the circumference of a circle:

Circumference = 2 * π * radius

The time for 1 revolution is 1/2s, since the body is whirled at a steady rate of 2rev/s.

Therefore, the velocity is:

Velocity = Circumference / Time
= 2 * π * radius / (1/2)
= 4 * π * radius
= 4 * 3.14 * 2
= 25.12m/s

Now we can calculate the centripetal force:

Centripetal force = 0.4kg * (25.12m/s)^2 / 2m
= 0.4kg * 630.2144m^2/s^2 / 2m
= 252.08576N

Therefore, the centripetal force is approximately 252N.

So, the answer is D. 252N.