Question

initial class boundary of
22.5
, an ending class boundary of
47.5
, and
5
classes of equal width.

Answer 1

initial class boundary of
16.5
and a class width of
5
.

Answer 2

initial class boundary of
1.5
, an ending class boundary of
13.5
, and
6
classes of equal width

Answer 3

initial class boundary of
0.5
, an ending class boundary of
45.5
, and
5
classes of equal width

Answer 4

The class width can be calculated by taking the difference between the ending class boundary and the initial class boundary, and then dividing it by the number of classes.

Class width = (Ending class boundary - Initial class boundary) / Number of classes

= (47.5 - 22.5) / 5

= 25 / 5

= 5

Therefore, the class width is 5.

Answer 5

To find the ending class boundary, we can calculate it by adding the class width to the initial class boundary.

Ending class boundary = Initial class boundary + Class width

= 16.5 + 5

= 21.5

Therefore, the ending class boundary is 21.5.

Answer 6

To find the class width, we can calculate it using the formula:

Class width = (Ending class boundary - Initial class boundary) / Number of classes

Class width = (13.5 - 1.5) / 6

Class width = 12 / 6

Class width = 2

Therefore, the class width is 2.

Answer 7

To find the class width, we can calculate it using the formula:

Class width = (Ending class boundary - Initial class boundary) / Number of classes

Class width = (45.5 - 0.5) / 5

Class width = 45 / 5

Class width = 9

Therefore, the class width is 9.