Question
Second harmonic motion of a string 1.5m long fixed at both ends 80HZ.The speed of transverse wave in the string is
Answers
GPT 3.5
To find the speed of the transverse wave in the string, we can use the formula:
v = λ * f,
where v is the speed of the wave, λ is the wavelength, and f is the frequency.
In this case, the length of the string is 1.5m and the frequency is 80Hz. Since the string is fixed at both ends, only half a wavelength fits on the string. Therefore, the wavelength is equal to twice the length of the string, or 2 * 1.5m = 3m.
Plugging in the values into the formula, we get:
v = 3m * 80Hz = 240 m/s.
Therefore, the speed of the transverse wave in the string is 240 m/s.
v = λ * f,
where v is the speed of the wave, λ is the wavelength, and f is the frequency.
In this case, the length of the string is 1.5m and the frequency is 80Hz. Since the string is fixed at both ends, only half a wavelength fits on the string. Therefore, the wavelength is equal to twice the length of the string, or 2 * 1.5m = 3m.
Plugging in the values into the formula, we get:
v = 3m * 80Hz = 240 m/s.
Therefore, the speed of the transverse wave in the string is 240 m/s.