What is the correct standard form of the equation of the parabola?

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Where the parabola is (2,-4)

3 answers

To determine the standard form of the equation of a parabola, we need additional information such as the vertex and the focus of the parabola.

Given that the parabola passes through the point (2, -4), we can infer that this point lies on the parabola. However, without any other information, we cannot determine the standard form of the equation of the parabola.
the diretix is (2,-5)
To find the equation of a parabola given its vertex (h, k) and directrix, we can use the formula:

(x - h)^2 = 4p(y - k)

where (h, k) is the vertex and (h, k + p) is the focus, and p is the distance between the vertex and the focus.

The given vertex is (2, -4), and the given directrix is the point (2, -5).

Since the directrix is a horizontal line, the parabola opens either upwards or downwards. Let's assume it opens upwards.

The vertex form of the equation becomes:

(x - 2)^2 = 4p(y + 4)

To find the value of p, we need to calculate the distance between the vertex and the directrix. Since the parabola opens upwards, p is positive and is equal to the distance between the vertex and the directrix.

Using the distance formula, we have:

p = |-5 - (-4)| = |-5 + 4| = |1| = 1

Substituting this value of p into the equation, we get:

(x - 2)^2 = 4(1)(y + 4)
(x - 2)^2 = 4y + 16
x^2 - 4x + 4 = 4y + 16

Expanding and rearranging the equation, we have:

x^2 - 4x - 4y - 12 = 0

Therefore, the standard form of the equation of the parabola with the vertex (2, -4) and directrix (2, -5) is:

x^2 - 4x - 4y - 12 = 0