an unknown substance with mass of 1.2 kg loses 32 kJ of thermal energy. which causes the temperature to drop from 364.0 k to 304.6 k. identify the unknown sustenance

Answer 1

To identify the unknown substance, we can use the formula for specific heat:

Q = mcΔT

Where:
Q is the thermal energy lost or gained
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature

Rearranging the formula, we get:

c = Q / (mΔT)

Plugging in the given values, we have:

c = -32 kJ / (1.2 kg * (304.6 K - 364.0 K))

Calculating the denominator first:

ΔT = 304.6 K - 364.0 K
ΔT = -59.4 K

Now, plugging in the values:

c = -32 kJ / (1.2 kg * -59.4 K)
c ≈ 0.449 kJ/(kg·K)

Using specific heat capacity tables or reference books, we can identify substances with a specific heat capacity close to 0.449 kJ/(kg·K).