To identify the unknown substance, we can use the equation for specific heat capacity:
Q = mcΔT,
where Q is the thermal energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
In this case, we are given Q as 32 kJ (which is equivalent to 32,000 J), m as 1.2 kg, and the initial and final temperatures as 364.0 K and 304.6 K, respectively.
Let's rearrange the equation to solve for the specific heat capacity (c):
c = Q / (m * ΔT).
c = 32,000 J / (1.2 kg * (304.6 K - 364.0 K))
c = 32,000 J / (1.2 kg * (-59.4 K))
c ≈ -449.83 J/(kg*K).
The specific heat capacity obtained (-449.83 J/(kg*K)) is negative, which is not physically possible. Therefore, there might be an error in the provided information or calculation. Please recheck the given data or calculations to get a valid value for the specific heat capacity.
an unknown substance with mass of 1.2kg loses 32 kJ of thermal energy. which causes the temperature to drop from 364.0 k to 304.6 k. identify the unknown sustenance
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