To find the square root of 3π to the nearest tenth, we can calculate the value as follows:
√(3π) ≈ √(9.42) ≈ 3.1
Therefore, the value of √(3π) to the nearest tenth is 3.1.
The correct answer is B) 3.1.
\sqrt{3\pi }\:to\:the\:nearest\:tenth
The answers:
A) 2.9
B) 3.1
C) 5.1
D) 5.3
6 answers
Find the rational number halfway between the two numbers in each pair.
(1/2) and (1/4)
All possible answers:
A) (1/8)
B) (3/4)
C) (3/8)
D) (1/4)
(1/2) and (1/4)
All possible answers:
A) (1/8)
B) (3/4)
C) (3/8)
D) (1/4)
To find the rational number halfway between (1/2) and (1/4), we need to find their average.
(1/2) + (1/4) = (2/4) + (1/4) = (3/4)
So, the rational number halfway between (1/2) and (1/4) is (3/4).
The correct answer is B) (3/4).
(1/2) + (1/4) = (2/4) + (1/4) = (3/4)
So, the rational number halfway between (1/2) and (1/4) is (3/4).
The correct answer is B) (3/4).
Solve the problem.
Jerry caught a fish that weighed 16(4/7) pounds. Pat caught a fish that weighed 9(5/7) pounds.
How much more did Jerry's fish weigh than Pat's fish?
Question 9 possible answers:
A) 25(6/7) lb
B) 6(6/7) lb
C) 24(6/7) lb
D) 6(5/7) lb
Jerry caught a fish that weighed 16(4/7) pounds. Pat caught a fish that weighed 9(5/7) pounds.
How much more did Jerry's fish weigh than Pat's fish?
Question 9 possible answers:
A) 25(6/7) lb
B) 6(6/7) lb
C) 24(6/7) lb
D) 6(5/7) lb
Well?
To find the difference in weight between Jerry's fish and Pat's fish, we subtract the weight of Pat's fish from the weight of Jerry's fish:
Weight of Jerry's fish: 16(4/7) pounds
Weight of Pat's fish: 9(5/7) pounds
16(4/7) - 9(5/7) = (112/7) - (68/7) = 44/7 = 6(2/7) pounds
Therefore, Jerry's fish weighs 6(2/7) pounds more than Pat's fish.
The correct answer is not listed among the given options.
Weight of Jerry's fish: 16(4/7) pounds
Weight of Pat's fish: 9(5/7) pounds
16(4/7) - 9(5/7) = (112/7) - (68/7) = 44/7 = 6(2/7) pounds
Therefore, Jerry's fish weighs 6(2/7) pounds more than Pat's fish.
The correct answer is not listed among the given options.