Question

X alpha (y÷z).x = 27 when y = 9 z= 2. (a) Find the relationship between x, y and z. (b) Find x when y =14 and z = 12.

Answer 1

First, let's solve for the value of x when y = 9 and z = 2.

Substituting y = 9 and z = 2 into the equation, we get:

X alpha (9÷2).x = 27

Simplifying the equation:

X alpha (4.5).x = 27

Multiplying 4.5 and x:

4.5x^2 = 27

Dividing both sides by 4.5:

x^2 = 6

Taking the square root of both sides:

x = ±√6

So the relationship between x, y, and z when y = 9 and z = 2 is x = ±√6.

Now, let's find x when y = 14 and z = 12.

Substituting y = 14 and z = 12 into the equation:

x alpha (14÷12).x = 27

Simplifying:

x alpha (7/6).x = 27

Multiplying (7/6) and x:

(7/6)x^2 = 27

Dividing both sides by (7/6):

x^2 = (27 * 6) / 7

x^2 = 162 / 7

Taking the square root of both sides:

x = ±√(162/7)