In a basketball game, Melina's ratio of 2bpoint shot attempts to 3 point shot attempts was 4:1. What percent of Melina's attempted shots were 3 point shots?

Answer 1

Let x be the ratio denominator.
The ratio of 2-point shot attempts to 3-point shot attempts is 4:1 or 4/1 = 4/4 = 1.
So, the ratio numerator is 4.
The 3-point shot attempts were 4 / 1 + 4 = 4/5*100 = <<4/5*100=80>>80% of Melina's attempted shots. Answer: \boxed{80}.