Question
1. Simplify and solve for x, 2x2 + 3y − 8y2 =
0
A. x = √(
𝑦(3−8𝑦)
2
)
B. x =
5𝑦
2
C. x =
𝑦(8𝑦−3)
2
D. X = √(
𝑦(8𝑦−3)
2
)
0
A. x = √(
𝑦(3−8𝑦)
2
)
B. x =
5𝑦
2
C. x =
𝑦(8𝑦−3)
2
D. X = √(
𝑦(8𝑦−3)
2
)
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
sorry, but (x - 3y)(2y - 3) ≠ 2x^2 - 8y^2 + 3y
Yet after all that bogus math, you cheated and managed to arrive at the correct answer ...
sorry, but (x - 3y)(2y - 3) ≠ 2x^2 - 8y^2 + 3y
Yet after all that bogus math, you cheated and managed to arrive at the correct answer ...
Answered by
Bot
To solve for x, you need to move all terms to one side of the equation and then factor the equation if possible.
Starting with the equation 2x^2 + 3y - 8y^2 = 0:
Rearranging the terms,
2x^2 - 8y^2 + 3y = 0.
Now, we can factor the equation by grouping:
2x^2 - 8y^2 + 3y = 0
2x^2 - 6y^2 - 2y + 3y = 0
2x^2 - 6y^2 - 2y + 3y = 0
2x(x - 3y) - y(2y - 3) = 0
Now, we have two factors, (x - 3y) and (2y - 3), that equals zero:
(x - 3y)(2y - 3) = 0
Setting each factor equal to zero and solving for x, we have:
x - 3y = 0 or 2y - 3 = 0
Solving the first equation, x - 3y = 0, we can isolate x by adding 3y to both sides:
x = 3y.
Solving the second equation, 2y - 3 = 0, we can add 3 to both sides and then divide by 2:
2y = 3
y = 3/2
Therefore, the solution for x is x = 3y, and substituting y = 3/2 into the equation, we get:
x = 3(3/2) = 9/2.
The correct answer is D. x = √( 𝑦(8𝑦−3)/2 )
Starting with the equation 2x^2 + 3y - 8y^2 = 0:
Rearranging the terms,
2x^2 - 8y^2 + 3y = 0.
Now, we can factor the equation by grouping:
2x^2 - 8y^2 + 3y = 0
2x^2 - 6y^2 - 2y + 3y = 0
2x^2 - 6y^2 - 2y + 3y = 0
2x(x - 3y) - y(2y - 3) = 0
Now, we have two factors, (x - 3y) and (2y - 3), that equals zero:
(x - 3y)(2y - 3) = 0
Setting each factor equal to zero and solving for x, we have:
x - 3y = 0 or 2y - 3 = 0
Solving the first equation, x - 3y = 0, we can isolate x by adding 3y to both sides:
x = 3y.
Solving the second equation, 2y - 3 = 0, we can add 3 to both sides and then divide by 2:
2y = 3
y = 3/2
Therefore, the solution for x is x = 3y, and substituting y = 3/2 into the equation, we get:
x = 3(3/2) = 9/2.
The correct answer is D. x = √( 𝑦(8𝑦−3)/2 )
Answered by
Bot
Apologies for the mistake in the initial explanation. I appreciate your understanding. As you correctly pointed out,
2x^2 - 8y^2 + 3y ≠ (x - 3y)(2y - 3)
Let's go through the correct solution:
Starting with the equation 2x^2 + 3y - 8y^2 = 0, we can rearrange it as:
2x^2 - 8y^2 + 3y = 0
Now, let's factor the equation:
2x^2 - 8y^2 + 3y = 0
2x^2 + 3y - 8y^2 = 0
2x^2 + y(3 - 8y) = 0
Now, we have a quadratic equation to solve for x. To factor it, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 2, b = y, and c = 3 - 8y:
x = (-y ± √(y^2 - 4(2)(3 - 8y))) / (2(2))
x = (-y ± √(y^2 - 24 + 64y)) / 4
x = (-y ± √(y^2 + 64y - 24)) / 4
Therefore, the correct simplified and solved equation for x is:
x = (-y ± √(y^2 + 64y - 24)) / 4.
Apologies again for the earlier mistake. Thank you for bringing it to my attention.
2x^2 - 8y^2 + 3y ≠ (x - 3y)(2y - 3)
Let's go through the correct solution:
Starting with the equation 2x^2 + 3y - 8y^2 = 0, we can rearrange it as:
2x^2 - 8y^2 + 3y = 0
Now, let's factor the equation:
2x^2 - 8y^2 + 3y = 0
2x^2 + 3y - 8y^2 = 0
2x^2 + y(3 - 8y) = 0
Now, we have a quadratic equation to solve for x. To factor it, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 2, b = y, and c = 3 - 8y:
x = (-y ± √(y^2 - 4(2)(3 - 8y))) / (2(2))
x = (-y ± √(y^2 - 24 + 64y)) / 4
x = (-y ± √(y^2 + 64y - 24)) / 4
Therefore, the correct simplified and solved equation for x is:
x = (-y ± √(y^2 + 64y - 24)) / 4.
Apologies again for the earlier mistake. Thank you for bringing it to my attention.
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