Question
Make t the subject of the familiar:
3๐
(๐๐กโ๐)
= 1 + U
A. t =
3๐
(1+ ๐ข}
+
๐
๐
B. t =
3๐
๐ฃ(1+ ๐ข}
+
๐
๐
C. t =
3
(1+ ๐ข}
+
๐
๐
D. 3
๐ฃ(1+ ๐ข}
+
๐
๐
3๐
(๐๐กโ๐)
= 1 + U
A. t =
3๐
(1+ ๐ข}
+
๐
๐
B. t =
3๐
๐ฃ(1+ ๐ข}
+
๐
๐
C. t =
3
(1+ ๐ข}
+
๐
๐
D. 3
๐ฃ(1+ ๐ข}
+
๐
๐
Answers
Bot
To make t the subject of the equation, we want to isolate t on one side of the equation.
Starting with the given equation:
(3๐) / (๐๐ก โ ๐) = 1 + U
We can start by multiplying both sides of the equation by (๐๐ก โ ๐) to eliminate the denominator:
3๐ = (๐๐ก โ ๐) * (1 + U)
Next, we distribute the (1 + U) term on the right side of the equation:
3๐ = ๐๐ก(1 + U) โ ๐(1 + U)
Expanding the equation further:
3๐ = ๐๐ก + ๐๐กU โ ๐ โ ๐U
Next, we want to gather all the terms containing ๐ก on one side of the equation. We do this by subtracting ๐๐ก from both sides:
3๐ - ๐๐ก = ๐๐กU โ ๐ โ ๐U
Rearranging the terms:
๐ก(3๐ โ ๐) = ๐๐กU โ ๐ โ ๐U
Finally, we want to isolate t, so we divide both sides of the equation by (3๐ โ ๐):
๐ก = (๐๐กU โ ๐ โ ๐U) / (3๐ โ ๐)
The final result is:
๐ก = (๐๐กU โ ๐ โ ๐U) / (3๐ โ ๐)
Therefore, the correct option is D. 3๐ฃ(1+ ๐ข)/(๐ฃ - ๐)
Starting with the given equation:
(3๐) / (๐๐ก โ ๐) = 1 + U
We can start by multiplying both sides of the equation by (๐๐ก โ ๐) to eliminate the denominator:
3๐ = (๐๐ก โ ๐) * (1 + U)
Next, we distribute the (1 + U) term on the right side of the equation:
3๐ = ๐๐ก(1 + U) โ ๐(1 + U)
Expanding the equation further:
3๐ = ๐๐ก + ๐๐กU โ ๐ โ ๐U
Next, we want to gather all the terms containing ๐ก on one side of the equation. We do this by subtracting ๐๐ก from both sides:
3๐ - ๐๐ก = ๐๐กU โ ๐ โ ๐U
Rearranging the terms:
๐ก(3๐ โ ๐) = ๐๐กU โ ๐ โ ๐U
Finally, we want to isolate t, so we divide both sides of the equation by (3๐ โ ๐):
๐ก = (๐๐กU โ ๐ โ ๐U) / (3๐ โ ๐)
The final result is:
๐ก = (๐๐กU โ ๐ โ ๐U) / (3๐ โ ๐)
Therefore, the correct option is D. 3๐ฃ(1+ ๐ข)/(๐ฃ - ๐)