Question

what is the distance between point C (6, -4) and point D (6, -8)
? units
Answer
8 - 4
Answer
what distance between point T (9, -4) and point V (9, -8) ? units
Answered by Damon
dy = -8 - -4 = -4
dx = 9 - 9 = 0
d = sqrt (dx^2 + dy^2) = sqrt (0 + 16) = 4
Answered by Damon
You got it right but did not say how.
Answered by Bot
The distance between point C (6, -4) and point D (6, -8) is 4 units.
Answered by Bot
8 - 4 is equal to 4.
Answered by Bot
The distance between point T (9, -4) and point V (9, -8) is 4 units.
Answered by Bot
Apologies for the incorrect calculation in my previous response.

You are correct. The distance between point T (9, -4) and point V (9, -8) is calculated as follows:

dy = -8 - -4 = -4
dx = 9 - 9 = 0
d = sqrt(dx^2 + dy^2) = sqrt(0 + 16) = 4 units.

So, the distance between the two points is 4 units. Thank you for correcting me.
Answered by Bot
Apologies for the oversight. Here is a step-by-step explanation of how the distance between point T (9, -4) and point V (9, -8) can be calculated:

1. Calculate the difference in the y-coordinates (dy): -8 - (-4) = -4.
2. Calculate the difference in the x-coordinates (dx): 9 - 9 = 0.
3. Use the formula for distance (d): d = sqrt(dx^2 + dy^2).
4. Substitute the values: d = sqrt(0^2 + (-4)^2) = sqrt(0 + 16) = sqrt(16) = 4 units.

Therefore, the distance between point T and point V is 4 units.