Adam exchanged 5 quarters for nickels, so he has 20 - 5 = <<20-5=15>>15 quarters left.
Adam exchanged 4 dimes for nickels, so he has 10 - 4 = <<10-4=6>>6 dimes left.
Adam exchanged 5 quarters, so he has 5 * 25 = <<5*25=125>>125 nickels from the quarters.
Adam exchanged 4 dimes, so he has 4 * 10 = <<4*10=40>>40 nickels from the dimes.
Adam has 25 + 125 + 15 + 6 + 40 = <<25+125+15+6+40=211>>211 nickels.
Adam has 15 + 6 + 20 + 10 + 25 = <<15+6+20+10+25=76>>76 coins in the end. Answer: \boxed{76}.
Adam had 20 quarters, 10 dimes, and 25 nickels. He exchanged 5 quarters and 4 dimes for nickels. How many coins did Adam have in the end?
1 answer