If we have nine distinct letters and we want to choose six of them without replacement, and the order of the choice matters, then we can use the permutation formula to determine the number of ways this can be done.
The permutation formula for choosing objects without replacement, where the order matters, is given by:
P(n, r) = n! / (n - r)!
Where n is the total number of objects and r is the number of objects chosen.
In this case, we have 9 distinct letters and we want to choose 6 without replacement. Plugging these values into the permutation formula, we get:
P(9, 6) = 9! / (9 - 6)!
= 9! / 3!
= (9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1) / (3 * 2 * 1)
= 9 * 8 * 7 * 6 * 5 * 4
= 604,800
Therefore, there are 604,800 ways to choose six letters without replacement from nine distinct letters when the order of the choice is taken into consideration.
Suppose we want to choose six letters without replacement from nine distinct letters if the order of the choice is taken into consideration how many ways can this be done
1 answer
1 answer