To find the number of moles of water of crystallization (x) in the compound, we need to determine the molar mass of water.
The molar mass of water (H2O) is the sum of the atomic masses of hydrogen (H) and oxygen (O):
H2O = (2 * 1.00784 g/mol) + (1 * 15.999 g/mol) = 18.015 g/mol
First, we need to calculate the molar mass of sodium carbonate (Na2CO3) by subtracting the molar mass of the water from the total molar mass of the hydrated sodium carbonate:
Molar mass of sodium carbonate = 268 g/mol - 18.015 g/mol = 249.985 g/mol
The molar mass of sodium carbonate (Na2CO3) is approximately 249.985 g/mol.
Now, let's determine the molar mass of Na2CO3 by considering the atomic masses of sodium (Na), carbon (C), and oxygen (O):
Na2CO3 = (2 * 22.9897 g/mol) + 12.01 g/mol + (3 * 15.999 g/mol) = 105.988 g/mol
Therefore, the molar mass of Na2CO3 is approximately 105.988 g/mol.
Now, we can calculate the number of moles of water (x) in the compound by dividing the molar mass of water (18.015 g/mol) by the molar mass of sodium carbonate (105.988 g/mol):
x = 18.015 g/mol / 105.988 g/mol
x โ 0.1699
Therefore, the number of moles of water of crystallization (x) in the hydrated sodium carbonate compound Na2CO3ยทxH2O is approximately 0.1699 moles.