Asked by silly_muffin
Another question. The law of iterated expectations tells us that E[E[X/Y]] = E[X]. Suppose that we want apply this law in a conditional universe, given another random variable Z, in order to evaluate E[X/Z]. Then, tell me if this is true or false, remember than more than one option can be true
a) E[E[X/Y,Z]/Z] = E[X/Z]
b) E[E[X/Y]/Z] = E[X/Z]
c) E[E[X/Y,Z]] = E[X/Z]
a) E[E[X/Y,Z]/Z] = E[X/Z]
b) E[E[X/Y]/Z] = E[X/Z]
c) E[E[X/Y,Z]] = E[X/Z]
Answers
Answered by
silly_muffin
why?
Answered by
Bot
a) True
b) False
c) False
b) False
c) False
Answered by
Bot
The correct answer is:
a) E[E[X/Y,Z]/Z] = E[X/Z]
This is true because according to the law of iterated expectations, we can simplify the expression E[E[X/Y,Z]/Z] as E[X/Y,Z]. Then, when we take the expectation of this expression with respect to Z, it collapses to E[X/Z]. Therefore, a) is true.
b) E[E[X/Y]/Z] = E[X/Z]
This is false because the law of iterated expectations does not allow us to swap the order of conditioning. In this case, E[E[X/Y]/Z] means taking the expectation of X conditional on Y first, and then taking the expectation of that result conditional on Z. But E[X/Z] means taking the expectation of X conditional on Z. Since these two are different conditioning sequences, b) is false.
c) E[E[X/Y,Z]] = E[X/Z]
This is also false for the same reason as option b). The law of iterated expectations does not allow us to swap the order of conditioning. E[E[X/Y,Z]] means taking the expectation of X conditional on Y and Z, while E[X/Z] means taking the expectation of X conditional on Z. Since the order of conditioning is different, c) is false.
a) E[E[X/Y,Z]/Z] = E[X/Z]
This is true because according to the law of iterated expectations, we can simplify the expression E[E[X/Y,Z]/Z] as E[X/Y,Z]. Then, when we take the expectation of this expression with respect to Z, it collapses to E[X/Z]. Therefore, a) is true.
b) E[E[X/Y]/Z] = E[X/Z]
This is false because the law of iterated expectations does not allow us to swap the order of conditioning. In this case, E[E[X/Y]/Z] means taking the expectation of X conditional on Y first, and then taking the expectation of that result conditional on Z. But E[X/Z] means taking the expectation of X conditional on Z. Since these two are different conditioning sequences, b) is false.
c) E[E[X/Y,Z]] = E[X/Z]
This is also false for the same reason as option b). The law of iterated expectations does not allow us to swap the order of conditioning. E[E[X/Y,Z]] means taking the expectation of X conditional on Y and Z, while E[X/Z] means taking the expectation of X conditional on Z. Since the order of conditioning is different, c) is false.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.