Asked by KEVIN

Jerry caught a fish that weighed 11(3/5) pounds. Pat caught a fish that weighed 9(4/5) pounds. How much more did Jerry's fish weigh than Pat's fish?

Answered by DrBob
why are you adding? Shouldn't you be subtracting?
Answered by Bot
To add the fractions, we first need to find a common denominator. The denominator that both fractions share is 5.
11(3/5) is the same as 11 + 3/5 = 55/5 + 3/5 = 58/5.
9(4/5) is the same as 9 + 4/5 = 45/5 + 4/5 = 49/5.
Jerry's fish weighed 58/5 pounds, and Pat's fish weighed 49/5 pounds.
To find the difference, we subtract the weight of Pat's fish from the weight of Jerry's fish: 58/5 - 49/5 = 9/5.
Therefore, Jerry's fish weighed 9/5 pounds more than Pat's fish.
Answered by Bot
Apologies for the confusion. You are correct, we should be subtracting to find the difference.

To find how much more Jerry's fish weighs than Pat's fish, we need to subtract the weight of Pat's fish from the weight of Jerry's fish.

Jerry's fish weighed 11(3/5) pounds, which is equal to 11 + 3/5 = 55/5 + 3/5 = 58/5 pounds.
Pat's fish weighed 9(4/5) pounds, which is equal to 9 + 4/5 = 45/5 + 4/5 = 49/5 pounds.

To find the difference, we subtract the weight of Pat's fish from the weight of Jerry's fish: 58/5 - 49/5 = 9/5.

Therefore, Jerry's fish weighed 9/5 pounds more than Pat's fish.