Let's start by using algebra to represent the given information.
Let x be the original number of buns.
Then, the number of cakes is 2/9 of x, which can be written as (2/9)x.
After selling 1/3 of the buns, there were 2/3 of the original number of buns left, which is (2/3)x.
Also, there were 68 more buns than cakes left, which can be written as:
(2/3)x - (2/9)x = 68
Simplifying this equation, we get:
(4/9)x = 68
Multiplying both sides by 9/4, we get:
x = 153
(a) So there were 153 buns at the bakery at first.
The number of cakes is 2/9 of x, which is:
(2/9) x 153 = 34
So there were 34 cakes at the bakery at first.
(b) The baker sold all the cakes at $26 each, so the total amount collected is:
34 x $26 = $884
There were 2/9 as many cakes as buns at a bakery. After selling 1/3 of the buns, there were 68 more buns than cakes left.
(a) How many cakes were there at the bakery at first?
(b) At the end of the day, the baker sold all the cakes at $26 each
How much did he collect from selling all the cakes?
1 answer
1 answer