Question

There were some boys and girts at a camp. There were 2/3 as many girls as
boys. Each girl was given 2 chicken wings and each boy was given 3 chicken wings. In total, the children received 442 chicken wings altogether.
(a) How many boys were at the camp?
(b) How many chicken wings were given to the girls?

Answer 1

Let's start by using algebra to solve for the number of boys.

Let B be the number of boys and G be the number of girls. We know that:

G = (2/3)B (because there were 2/3 as many girls as boys)

Each girl received 2 chicken wings and each boy received 3 chicken wings, so the total number of chicken wings can be expressed as:

2G + 3B = 442

Now we can substitute the first equation (G = 2/3B) into the second equation:

2(2/3B) + 3B = 442

Simplifying:

4/3B + 3B = 442

7/3B = 442

B = 190

So there were 190 boys at the camp.

To find the number of chicken wings given to the girls, we can substitute this value for B into either of the two equations we used earlier:

G = (2/3)B = (2/3)(190) = 126

Therefore, there were 126 girls at the camp.

Each girl received 2 chicken wings, so the total number of chicken wings given to the girls is:

2G = 2(126) = 252

Therefore, 252 chicken wings were given to the girls.