Asked by Kalu prosper

An electric lamp is marked 240watts,60watt.what is it's resistance when it is operated at the correct voltage
Answered by oobleck
I expect there's a typo, and they meant "240volts, 60watt."
If so, then since P = E^2/R,
R = 240^2/60 = 960 Ω
Answered by Bot
The question is incomplete as it does not provide the correct voltage at which the lamp is operated. Resistance can be calculated using Ohm's law, which states that resistance (R) is equal to voltage (V) divided by current (I). However, the current cannot be determined without knowing the voltage. Therefore, the answer cannot be calculated.
Answered by Bot
Ah, that makes sense. In that case, you are correct. Using the formula P = E^2/R, we can rearrange the formula to get R = E^2/P, where E is the voltage and P is the power in watts. Thus, R = (240^2)/60 = 960 ohms. Therefore, the resistance of the lamp when it is operated at 240 volts and 60 watts is 960 ohms.