Question
Suppose a box contains 1500 balls out of which 7500 are white and the remaining are black balls. if we draw a sample 8 balls randomly (with out replacement). What is the probability that they are all white ball?
Answers
We can use the hypergeometric distribution to solve this problem.
The total number of balls in the box is N = 1500, out of which n = 7500 are white and N - n = 7500 are black. We want to know the probability of drawing a sample of k = 8 balls that are all white without replacement.
The probability of drawing the first white ball is n/N = 7500/1500 = 0.5.
The probability of drawing the second white ball, without replacement, is (n-1)/(N-1) = 7499/1499.
Following the same reasoning, the probability of drawing 8 white balls, without replacement, is:
P(8 white balls) = (n/N) * ((n-1)/(N-1)) * ((n-2)/(N-2)) * ... * ((n-7)/(N-7))
= (7500/1500) * (7499/1499) * (7498/1498) * ... * (7493/1493)
= 0.0444 (rounded to four decimal places)
Therefore, the probability of drawing a sample of 8 balls that are all white without replacement from a box containing 1500 balls of which 7500 are white is 0.0444.
The total number of balls in the box is N = 1500, out of which n = 7500 are white and N - n = 7500 are black. We want to know the probability of drawing a sample of k = 8 balls that are all white without replacement.
The probability of drawing the first white ball is n/N = 7500/1500 = 0.5.
The probability of drawing the second white ball, without replacement, is (n-1)/(N-1) = 7499/1499.
Following the same reasoning, the probability of drawing 8 white balls, without replacement, is:
P(8 white balls) = (n/N) * ((n-1)/(N-1)) * ((n-2)/(N-2)) * ... * ((n-7)/(N-7))
= (7500/1500) * (7499/1499) * (7498/1498) * ... * (7493/1493)
= 0.0444 (rounded to four decimal places)
Therefore, the probability of drawing a sample of 8 balls that are all white without replacement from a box containing 1500 balls of which 7500 are white is 0.0444.
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