To calculate the vapour density of the gas, we need to know the molar mass of the gas. We can use the ideal gas law to find out the number of moles of gas present in the given volume:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At standard temperature and pressure (STP), P = 1 atm and T = 273 K. We are given that V = 5.6 dm3 and the molar volume of gas at STP is 22.4 dm3. Therefore, the number of moles of gas present is:
n = (PV)/(RT) = (1 atm)(5.6 dm3)/(0.08206 L atm/mol K)(273 K) = 0.229 mol
Next, we can calculate the molar mass of the gas using the given mass and the number of moles:
molar mass = (mass)/(number of moles) = 11 g/0.229 mol = 48 g/mol
Finally, we can calculate the vapour density of the gas, which is defined as the ratio of the molar mass of the gas to the molar mass of hydrogen (which has a vapour density of 1):
vapour density = (molar mass of gas)/(molar mass of hydrogen) = 48 g/mol/2 g/mol = 24
Therefore, the vapour density of the gas is 24.
If 11g of gas occupies 5.6dm3 at s.t.p calculate it's vapour density (molar volume = 22.4dm3 at s.t.p
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