The atmospheric pressure above a swimming pool changes from 755 to 765mm of mercury. The bottom of the pool is a 12m x 24m rectangle. By how much does the force on the bottom of the pool increase?

1 answer

To calculate the force on the bottom of the pool, we need to first calculate the area of the bottom:

Area = length x width = 12m x 24m = 288m²

Next, we need to calculate the change in pressure:

ΔP = P2 - P1 = 765mmHg - 755mmHg = 10mmHg

We convert the pressure to SI units (Pascals) for the calculation:

1mmHg = 133.322 Pa

ΔP = 10mmHg x 133.322 Pa/mmHg = 1333.22 Pa

Finally, we can calculate the increase in force using the formula:

Force = pressure x area

ΔF = ΔP x Area = 1333.22 Pa x 288m² = 384057.6 N

Therefore, the force on the bottom of the pool increased by approximately 384058 N.