how do i write an equation in point slope form when the slope= -1/2 and it passes through (5,-8) and then how do i write an equation for the line in slope-intercept form? thanks

Answer 1

slope point is y-y1=m(x-x1)
slope intercept is y=mx+b

slope point: y+8=-1/2(x-5)
solving gives us the slope intercept form of y=-1/2x-11/2

Answer 2

thanks :)

Answer 3

wouldnt it be -1/2x + 11/2 because negative 1/2 times a negative 5 would be 11/2...i think

Answer 4

no because -1/2*-5= 5/2-8=-11/2

Answer 5

sorry your right i wrote something wrong down :)